A 0.013 kg rubber stopper attached to a 1.8 m string is swung in a circle. If the tension in the string is 0.35 N, what is the period of the stopper's revolution?

where's the following? you gotta add it to know what the choices are

explanation:

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg

answergravity;