A 24 g bullet enters a 2.4 kg watermelon with a speed of 217 m/s and exits the opposite side with a speed of 107 m/s. If the melon was originally at rest, then what speed will it have as the bullet leaves its opposite side?

The magnets are probably damaged or there not strong enough to attached to the refrigerator

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.

Iwould think it would be 2.6