What is the magnitude of the force required to stretch or compress a spring of spring constant 50.0 N/m a distance 2.50 cm from its unstrained length? a. 50.0 N
b. 125 N
c. 20.0 N
d. 1.25 N

Magnitude of the force = 1.25 N

Explanation:

Given:

Spring constant k = 50.0 N/m

Distance s = 2.50 cm = 0.025 m

Find:

Magnitude of the force

Computation:

Magnitude of the force = Ks

Magnitude of the force = 50 x 0.025

Magnitude of the force = 1.25 N

explanation:

areas w steep slopes, west coast, rocky mountains, and appalachian mountains

1/0.14nm = 10^10/1.4 a lot