before colliding, the momentum of block a is -100 kg*m/s and block b is -150 kg*m/s. after, block a has a momentum of -200 kg*m/s. what is the momentum of block b afterwards?

Ibelieve the answer is b. dugout

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.

Dshould be the right answer i think