A 0.50-kilogram frog is at rest on a rock next to a pond. The frog leaps pushing off of the rock with an acceleration of 5.0 m/s2. What is the magnitude of the net force exerted on the frog as it leaps? a)2.5 N b)1.5 N c)1.0 N d)2.0 N

The magnitude of the net force exerted on the frog as it leaps is 2.5 Newtons.

Hence, Option a) 2.5N is the correct answer.

Given the data in the question;

Force Exerted;

To determine the magnitude of the net force exerted on the frog as it leaps, we the expression from the Newton's Second law of motion:

Where m is mass and a is acceleration

We substitute our given values into the equation

The magnitude of the net force exerted on the frog as it leaps is 2.5 Newtons.

Hence, Option a) 2.5N is the correct answer.  

Learn more on Newton's Second law of motion here: link

Given that,

Mass of a frog, m = 0.5 kg

The frog leaps pushing off of the rock with an acceleration of 5.0 m/s².

To find,

The magnitude of the net force exerted on the frog as it leaps.

Solution,

Let the net force exerted on the frog is given by the formula as follows :

F = ma

Putting the values of m and a to find F as follows :

F = 0.5 kg × 5 m/s²

F = 2.5 N

So, the magnitude of net force is 2.5 N.