In a house, 3 bulbs of 60 watt each are lighted for 3 hours daily, 4 fans of 100 watt each are used for 8 hours daily and an electric heater of 2 kwh used for half an hour daily. Calculate the total energy consumed in a month of 31 days and its cost at the rate of Rs 4/kwh.

Total Energy consumed = 146.94 kwh

Total cost = rs 587.76

Explanation:

Given:

3 bulbs each 60 watt [for 3 hours daily]

4 fans each 100 watt [for 8 hours daily

1 electric heater of 2 kWh (2,000 watt) [for half hour daily ]

Rate = rs 4/Kwh

Find:

Total Energy consumed

Total cost

Computation:

Energy used = Power × time

3 bulbs each 60 watt [for 3 hours daily]  = 3 x 60 x 3 x 31 = 16,740 watt = 16.74 kw

4 fans each 100 watt [for 8 hours daily  = 4 x 100 x 8 x 31 = 99,200 watt = 99.2 kw

1 electric heater of 2 kWh [for half hour daily ] = 1 x 2000 x (1/2) x 31 = 31,000 watt = 31 kw

Total Energy consumed = 16.74 + 99.2 + 31

Total Energy consumed = 146.94 kwh

Total cost = 146.94 x 4

Total cost = rs 587.76

which three statements are true about all alloys?