A water-skier of mass 75.0 kg initially at rest is being pulled due east by a horizontal towrope. The rope exerts a force of 365 N (east). The water (and air) exerts a combined average frictional force of 190 N (in the opposite direction). How fast will the skier be moving after a distance of 38.0 m?

The skier will be moving at 13.31 m/s.

Explanation:

To calculate the velocity of the skier we need to find the acceleration, as follows:

Where:

: is the force due to the rope = 365 N

: is the combined average frictional force = 190 N

m: is the mass = 75.0 kg

Now, we can calculate the velocity of the skier by using the following kinematic equation:

Where:

: is the final velocity =?

: is the initial velocity = 0 (the skier is initially at rest)

d: is the distance = 38.0 m

Therefore, the skier will be moving at 13.31 m/s.

I hope it helps you!                                                                                  

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