A horizontal wire PQ is perpendicular to a uniform horizontal magnetic field. A length of 0.25 m of the wire is subject to a magnetic field strength of 40 mT. A downward magnetic force of 60 mN acts on the wire. What is the magnitude and direction of the current in the wire

Complete question:

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The magnitude of the current is 6 A, in the direction of Q to P.

Explanation:

Given;

length of the wire, l = 0.25 m

magnetic field strength, B = 40 mT = 0.04 T

Magnitude of the magnetic force, F = 60 mN = 0.06 N

The magnitude of the current in the conductor is given as;

F = BIL

Where;

I is the current induced in the conductor

I = F / BL

I = (0.06) / (0.04 x 0.25)

I = 6 A

Th current will move in direction of Q to P

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

6 times more

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