In a hydraulic garage lift, the smallpiston has a radius of 5.0 cm and the large piston has a radius of15 cm. What force must be applied on the small piston in order tolift a car weighing 20,000 N on the large piston? a. 6.7 ×103 N
b. 5.0 ×103 N
c. 2.9 ×103 N
d. 2.2 ×103 N

Option  d) 2.2 × 10³ N is the correct answer

Explanation:

Given that;

radius of A₁ = 5.0

large piston has a radius of A₀ = 15 cm

Weight F₀ = 20,000 N

Force that must be applied to lift the weight F₁ = ?

Now we know that from Pascal Law

ΔP ⇒ F₁/A₁ = F₀/A₀

F₁ =  (F₀/A₀)A₁

where A = πr²

so we substitute

F₁ =  (20,000 / π(15²)) × π(5²)

= (20,000 / 706.8583) × 78.5398

= 2222.22 ≈ 2.2 × 10³ N

Therefore Option  d) 2.2 × 10³ N is the correct answer.

choosing tennis and golf balls is your inde choice.

their mass and volume are dep

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2