The water drops fall at regular intervals from a tap 5 m above the ground. The third drop is leaving the tap at the instant the first touches the ground. How far above the ground is the second drop at that instant? I will mark brainliest

The second drop is 3.75 m above the ground

Explanation:

Free Fall Motion

A free-falling object falls under the sole influence of gravity without air resistance.

If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is .

The distance traveled by a dropped object is:

If we know the height h from which the object was dropped, we can find the time it takes fo hit the ground:

When the first drop touches the ground there are two more drops in the air: the second drop still traveling, and the third drop just released from the tap.

The total time taken for the first drop to reach the ground is:

Half of this time has taken the second drop to fall:

It has fallen a distance of:

Thus its height is:

h = 5 - 1.25 = 3.75

The second drop is 3.75 m above the ground

pe = weightxheight = 2000x1000=2,000,000joules

your answer is, orbit around the nucleus