URGENT‼ An amateur marksman aims directly at a bulls-eye (on the same level) 75.0 m away. If the bullet leaves the gun at a speed of 180 m/s, by how much will it miss the target?

Hello!

He will miss it by ≈ 0.852 m

Begin by finding the amount of time necessary to hit the target. Use the formula t = d / s:

t = 75 / 180 = 0.4167 sec

Use the equation d = vi + 1/2at² to solve for the amount the bullet will miss the target. (vi is 0 in this instance). We are solving for the vertical component, so use a  = 9.81 m/s (gravity).

d = 0 + 1/2(9.81)(0.4167²)

d ≈ 0.852 m

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