An object is at rest when it undergoes a constant acceleration of 13 m/s2 for 5.0 seconds.
How far will it have traveled during this time?

Hi there!

Find the distance traveled using the kinematic equation:

d = vi(t) + 1/2(a)(t²)

In this instance, vi = 0 because the object was initially at rest. Plug in the other values to solve:

d = 0t + 1/2(13)(5²)

d = 1/2(13)(25)

d = 162.5m

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000