A 0.155 kg arrow is shot upward at 31.4 m/s. What is its kinetic
energy (KE) when it leaves the
bow?

2.43J

Explanation:

Given parameters:

Mass of the arrow = 0.155kg

Velocity = 31.4m /s

Unknown:

Kinetic energy when it leaves the bow = ?

Solution:

The kinetic energy of a body is the energy in motion of the body;

 it can be derived using the expression below:

   K.E  =  m v²

m is the mass

v is the velocity

 Solve for K.E;

    K.E  =    x 0.155 x 31.4 = 2.43J

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge