If an object has a weight of 4050 N near the surface of the Earth, what is its mass?

417.5 kg

Explanation:

Since the gravitational for of attraction F, equals the weight of the object W when its close to the earth, F = GMm/R² = W = mg where m = mass of object and g = acceleration due to gravity close to the earth = 9.8 m/s².

g = GM/R² where  g = acceleration due to gravity close to the earth, G = universal gravitational constant = 6.67 × 10⁻¹¹ Nm²/kg², M = mass of earth = 5.927 × 10²⁴ kg and R = radius of earth = 6.4 × 10⁶ m

So, g = GM/R²

= 6.67 × 10⁻¹¹ Nm²/kg² × 5.927 × 10²⁴ kg/(6.4 × 10⁶ m)²

= 39.53 × 10¹³ Nm²/kg ÷ 40.96 × 10¹² m²

= 9.65 N/kg

≅ 9.7 N/kg

= 9.7 m/s²

Since W = 4050 N and W = mg

m = W/g = 4050 N/9.7 m/s²

= 417.53 kg

≅ 417.5 kg

So, the mass of the object is 417.5 kg

answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.