A car is driving across a street. It's change in displacement is 50 m. If it started with a velocity of 5 m/s and ended with a velocity of 7 m/s, what must the acceleration have been?

Ew an sao fan. anyway, it's 0.24m/s^2

Explanation:

Use this equation for 1 dimensional motion with constant acceleration:

Xf = Xi + Vi*T + 0.5A*T^2

Xf is 50 m when Xi is 0m

Vi is 5m/s

A is (7m/s-5m/s)/T = 2m/s/T

So,

50m = 0m + 5m/s *T + 0.5*2m/s/T * T^2

50m = 5m/s * T + 1m/s * T

50m = 6m/s * T

T = 8.33s

A is 2m/s/T

A is 2m/s/8.33s

A is 0.24m/s^2

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

don't remove my answer im trying my best to answer them

explanation:

the motion of a pendulum is a classic example of mechanical energy conservation. a pendulum consists of a mass (known as a bob ) attached by a string to a pivot point. as the pendulum moves it sweeps out a circular arc, moving back and forth in a periodic fashion.