A square coil of wire with 15 turns and an area of 0.40 m2 is placed parallel to a magnetic field of 0.75 T. The coil is flipped so its plane is perpendicular to the magnetic field in 0.050 s. What is the

90 V

Explanation:

What is the magnitude of the average induced emf in the coil?

Given that

The number of turns, N = 15

Area of coil, A = 0.4 m²

Magnetic field of the coil, B = 0.75 T

Time taken, t = 0.05 s

The average induced EMF in a coil due to the presence of a magnetic field is given as:

v = -NBA/t

When we substitute the values directly, we have

v = - (15 * 0.4 * 0.75)/0.05

v = -4.5 / 0.05

v = -90

Therefore, the magnitude of the induced emf is 90 V

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