A slingshot consists of a light leather cup containing a stone. The cup is pulled back against two parallel rubber bands. It takes a force of 15 N to stretch either one of these bands 1.0 cm. (a) What is the potential energy stored in the two bands together when a 58-g stone is placed in the cup and pulled back 0.10 m from the equilibrium position?

the potential energy stored in two bands is 15J

Explanation:

The computation of the potential energy stored in two bands is as follows:

Given that

F = 15N

x = -1.00 m = -0.01m

F = -kx

k = -F ÷ x

= 15N ÷ 0.01m

= 1,500 N/m

Now the potential energy would be

= 1,500N/m × (-0.10m)^2

= 15J

hence, the potential energy stored in two bands is 15J

The same is to be considered

a

explanation:

because they are cartillidge

v=ir = 3x15 =45 v