An electric field with an average magnitude of about 175 N/C points downward in the atmosphere near Earth's surface. We wish to "float" a sulfur sphere weighing 7.4 N in this field by charging the sphere. What charge (both sign and magnitude) must be used?

q = 42.3 x 10⁻³ C = 42.3 mC

Explanation:

in order for the Sulphur charge to float the weight of the charge must be equal to the electric force:

where,

q = charge required = ?

W = Weight = 7.4 N

E = Electric Field Strength = 175 N/C

Therefore,

q = 42.3 x 10⁻³ C = 42.3 mC

answer; /// the above statement is (true);

b

step-by-step explanation: a third of 24 is 8, 8 times 3 is 24 so 8 - 2 would be 6