Un camion de 7500 kgg que viaja a 5.0 m/s hacia el este choca con un automovil de 1500 kg que se mueve a 20m/s en dirección 30° suroeste. Depues de la colisión, los dos vehiculos queda unidos ¿con que rapidez y en que direccion se mueven los vehiculos?

Responder:

2,1 m / s

53 °

Explicación:

Dado que:

M1 = 7500 kilogramos

V1 = 5 m / s

M2 = 1500 kilogramos

V2 = 20 m / s

Dado que ambos autos se unen después de la colisión (colisión inelástica)

M = M1 + M2 = 1500 + 7500 = 9000

M1V1 - M2V2cos α = MVx

((7500 * 5) - (1500 * 20 * cos30)) / 9000 = Vx

Vx = 1,2799153

Vx = 1,28 m / s

Vy = (M2V2 * sen α) / M

Vy = (- 1500 x 20 * sin30) / 9000

Vy = - 1,667 m / s

Velocidad después de la colisión (V):

V = √Vx² + Vy²

V = raíz cuadrada (1.28 ^ 2 + (-1.667) ^ 2)

V = 2,1017347

V = 2,1 m / s

Dirección:

Tanα = (Vy / Vx)

α = tan ^ -1 (-1,67 / 1,28)

α = 52,531 = 53 °

a small object of mass 3.66 g and charge -17.6 µc is suspended motionless above the ground when immersed in a uniform electric field perpendicular to the ground. what are the magnitude and direction of the electric field?

hello, i am papaguy.

i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!