What’s the acceleration of a car that goes from 32 m/a to 96 m/s in 8.0 s

Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt.  This is:

a = Δv / Δt

a = (96 m/s - 32 m/s) / (8.0 s)

a = 64 m/s / 8 s

d is the correct answer

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s