Dennis the Menace is shooting a rock with his slingshot with an initial height of 5 feet. The height in feet, of the rock above the ground is given by s(t)=-16t^2+44t+5, where t is time in seconds and t is >= 0. At what time will the rock be 15 ft above the ground?

The rock will be 15ft above the ground 0.25 and 2.5secs after

The height of the rock above the ground is expressed according to the expression

In order to get the time the rock will be 15ft above the ground, we will substitute s(t) = 15 ft into the formula above;

Factorize the expression to get the value of "t"

2(4t−1)(2t−5) = 0

4t - 1 = 0

4t = 1

t = 0.25secs

Similarly 2t - 5 =0

2t = 5

t = 5/2 = 2.5secs

This shows that the rock will be 15ft above the ground 0.25 and 2.5secs after

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 32

The average velocity of the rock would be 32 ft per second.

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min