n a double-slit experiment, the slit separation is 6.03x10-5 meters. The slits are illuminated with a laser beam of wavelength 5.37x10-7 meters. A screen is located 2.14 m from the slits. Calculate the distance on the screen from the first dark fringe on one side of the central maximum to the second dark fringe on the other side.

D = 3.81 x 10⁻² m = 3.81 cm

Explanation:

We can use the formula of fringe spacing from Young's Double Slit experiment to answer this question:

where,

Δx = distance between two consecutive dark fringes

λ = wavelength of light beam = 5.37 x 10⁻⁷ m

L = Distance between screen and slits = 2.14 m

d = slit separation = 6.03 x 10⁻⁵ m

But, we need the distance between first dark fringe on 1 side to 2nd dark fringe on other side. It means we need twice the distance between two dark fringes:

where,

D = distance between first dark fringe on one side and 2nd dark fringe on other side of central maximum = ?

Therefore,

D = 3.81 x 10⁻² m = 3.81 cm

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

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