What is the percent by mass of 5.0 g of iron (ii) sulfate dissolved in 75.0 grams of water?

Hello!

What the percent by mass of 5.0 g of iron (II) sulfate dissolved in 75.0 g of water?

We have the following data:

m1 (solute mass - iron II sulfate) = 5.0 g

m2 (solvent mass - water) = 75.0 g

m (solution mass) = m1 + m2 = 5.0 + 75.0 = 80.0 g

%m/m (percent mass by mass) = ?

We apply the data to the formula

The percent by mass of solute and mass solution of Iron II Sulfate is 6.25%  

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the answer is a. at the equator

explanation:

v=uf/(u-f)

= 5.-10/(5+10) convex lens has negative focal length