A 2.0-kg block starts from rest on the positive x axis 3.0 m from the origin and thereafter has an acceleration given by in m/s2. At the end of 2.0 s its angular momentum about the origin is:

hello your question is incomplete below is the complete question

A 2.0 kg block starts from rest on a positive x axis 3.0m from the origin and thereafter has an acceleration given by a= 4.0i - 3.0jin m/s2. At the end of 2.0 s, its angular momentum about the origin is .

answer : L = ( 2 kg ) [(-18m^2/s)k]

Explanation:

velocity vector(v)  = (4.0i - 3.0j )(2.0s)

position vector(r) = ( 3.0m)i

determine the angular momentum about the origin

L = m ( r * v )

attached below is the detailed solution

the most reliable source of information.is wikipedia

explanation:

newton's third law, for every action there is an equal and opposite reaction.