A 50 Kg football player is standing still when he experiences an inelastic collision with a 150 Kg football player who is traveling at 10 m/s. What is the velocity of the player immediately after the collision?

V = 7.5 m/s

Explanation:

Given that,

Mass of player 1, m₁ = 50 kg

Mass of player 2, m₂ = 150 kg

50 kg player stands still and 150 kg player is traveling at 10 m/s

We need to find the velocity of the player immediately after the collision. As the inelastic collision occurs. The linear momentum will remain conserved. After the collision, let they move with a constant velocity say V.So,

So, the velocity of the player immediately after the collision is 7.5 m/s.

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//