Describe the relationship between the weight of water in the catch bucket and the object in the beaker. a. the weight of the volume of the water is less than the buoyant force of the object. b. the weight of the volume of the water is equal to the buoyant force of the object. c. the weight of the volume of the water is greater than the buoyant force of the object. d. the weight of the volume of the water is not a factor in the buoyant force of th

The statement which best describe sthe relationship between the weight of water in the catch bucket and the object in the beaker is definitely  B. The weight of the volume of the water is equal to the buoyant force of the object, according to the Archimedes' principle in which is  said that weight of the fluid that would occupy the column is equal to water. I am pretty sure it will help.

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j