The second floor of a house is 6 m above the street level. How much work is required to lift a 300-kg refrigerator to the second-story level?

Work done, W = 18 kJ

Explanation:

Given that,

The mass of a refrigerator, m = 300 kg

The second floor of a house is 6 m above the street level.

We need to find the work required to lift the refrigerator to the second-story level.

Work done, W = F × d

Putting all the values,

W = 300 × 10 × 6

W = 18000 J

or

W = 18 kJ

So, 18 kJ of work is done in lifting the refrigerator to the second-story level.

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