An electron and a proton have charges of an equal magnitude but opposite sign of 1.60 x 10^-19 C. If the electron and proton in a hydrogen atom are separated by a distance of 4.20 x10^-11 m, what are the magnitude and direction of the electrostatic force exerted on the electron by the proton?

i. F =  1.3 x N

ii. The direction of the force of attraction exerted by the proton on the electron is towards the itself (i.e a pull).

Explanation:

Since the given charges are opposite, then the force of attraction is experienced. The force of attraction between the two charges can be determined by:

F =

where F is the force, k is the constant, is the charge of the electron, is the charge on the proton, and d is the distance between them.

So that; k = 9.0 x N , = 1.6 x C, = 1.6 x

Thus,

F =

  =

  = 1.3061 x

F = 1.3 x N

The force between the charges is 1.3 x N.

ii. The direction of the force of attraction exerted by the proton on the electron is towards the itself.

muscle endurance

explanation:

i can do 50 in a row ( but i get so tired after that)

found in the nucleus

has mass of one amu