A small object moves along the x-axis with acceleration ax(t) = −(0.0320m/s3)(15.0s−t). At t = 0 the object is at x = -14.0 m and has velocity v0x = 7.10 m/s.

Complete Question

A small object moves along the x-axis with acceleration ax(t) = −(0.0320m/s3)(15.0s−t)−(0.0320m/s3)(15.0s−t). At t = 0 the object is at x = -14.0 m and has velocity v0x = 7.10 m/s. What is the x-coordinate of the object when t = 10.0 s?

The position of the object at t = 10s is  

Explanation:

From the question we are told that

The acceleration along the x axis is  

  The position of the object at t = 0 is  x = -14.0 m

  The velocity at t = 0 s is  

Generally from the equation for acceleration along x axis we have that

=>  

=>  

At  t =0  s   and  

=>  

=>        

So  

=>  

=>  

At  t =0  s   and   x = -14.0 m

=>  

So

At  t = 10.0 s

=>  

d. air pressure decreases as altitude increases.