Physics, 28.11.2020 01:00 krisbarnett5353

1. A particular lever is 90.0% efficient. If 50.0 J of work are done on the lever, then how much work does the lever do on its load? 2.The mechanical advantage of a pulley system is 4.00. Using this pulley system, how much force do you need to exert to lift a 500.0 N box?

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Answer from: paaoolav

1. The work done by the lever on its load is 45 J

2. The force needed to exert to lift the load is 125 N.

1. Determination of the work done by the lever on the load.

Work Input = 50 J

Efficiency = 90%

Work Output =?

$efficiency \: = \frac{work \: output}{work \: input} \times 100 \\ \\ 90\% = \frac{work \: output}{50} \\ \\ cross \: multiply \\ \\ work \: output \: = 90\% \: \times 50 \\ \\ work \: output = 0.9 \: \times 50$

Work Output = 45 J

Therefore, the work done by the lever on the load is 45 J

2. Determination of the force needed to lift the load

Mechanical advantage (MA) = 4

Load (L) = 500 N

Effort (E) = ?

$mechanical \: advantage \: = \frac{load}{effot} \\ \\ 4 \: = \frac{500}{effort} \\ \\ cross \: multiply \\ \\ 4 \: \times effort \: = 500 \\ \\ divide \: both \: side \: by \: 4 \\ \\ effort \: = \frac{500}{4} \\$

Effort = 125 N

Therefore, the force needed to lift the load is 125 N

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Answer from: ccollingwood

Explanation:

Using the efficiency formula;

Efficiency = Work done by the machine (output)/work done on the machine (input) ×100%

Efficiency =w/50 ×100

90 = 100w/50

Cross multiply

90×50 = 100W

4500 = 100W

W = 4500/100

W = 45Joules

Hence the lever does 45Joules of work on its load

2) Mechanical Advantage= Load/Effort

Given

MA = 4

Load = 500N

4 = 500/Effort

Effort = 500/4

Effort =125N

Hence the effort required to lift the load is 125N

Answer from: Quest

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

$_a^z\textrm{x}\rightarrow _{a-2}^{z-4}+_2^4\alpha$

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

$_a^z\textrm{x}+_{-1}^0\textrm{e}\rightarrow _{z-1}^a\textrm{y}$

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases $\gamma -radiations$ . this process does not change the mass number.

$_a^z\textrm{x}^*\rightarrow _a^z\textrm{x}+_0^0\gamma$

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as $\beta ^+$ -decay. in this the mass number remains same.

$_a^z\textrm{x}\rightarrow _{z-1}^a\textrm{y}+_{+1}^0e$

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

Answer from: Quest

grav force prop 1/r squared 2r all squared is 4rsquared 1/4rsquared quartered

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