A 60.0-cm, uniform, 5.00-kg shelf is supported horizontally by two vertical wires attached to a sloping ceiling. The front wire is inset by a distance of 20 cm. A very small 2.50-kg tool is placed on the shelf midway between the points where the wires are attached to it. Required:

Find the tension in the back wire.

The tension in the back wire equals 24.5 N.

We can arrive at this answer with the static equilibrium formula, for that, let's consider that the tension in the back wire is represented by the letter "t," while the tension in the front wire is represented by the letter "T."

Therefore, we can use the following formula:

In this case, the letter "W" refers to the tool weight, while the letter "g" refers to gravity.

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Tension in back wire = 24.5 N

Explanation:

let the tension in the back wire be Tₒ

let the tension in the front wire be T

Applying static equilibrium in the vertical direction, we have:

T + Tₒ = (5 × 9.8) + (2.5 × 9.8)

T + Tₒ = 73.5

Where Tₒ = (2.5 × 9.8) = 24.5 N

Thus, Tension in back wire = 24.5 N