At an air show a jet flies at speed 1500 km/h on a day when the speed of sound is 342 m/s. What is the angle of the shock cone

55 degrees

Explanation:

Given that an air show a jet flies at speed 1500 km/h on a day when the speed of sound is 342 m/s.

From the question above, we can get the below parameters

Object speed (V) = 1500 km/h

Sound speed ( v) = 342 m/s

Convert km/h to m/s

(1500 × 1000)/3600

Jet speed V = 416.67 m/s

Let's first calculate the mash number M.

M = V/v

M = 416.67 / 342

M = 1.2183

Formula for the angle of the shock cone is reciprocal of mash number. That is,

Sin Ø = 1 / M

Sin Ø = 1 / 1.2183

Sin Ø = 0.8208

Ø = sin^-1(0.8208)

Ø = 55 degree

Therefore, the angle of the shock cone is approximately 55 degrees

what is the actual question though?