A 2.93 kg particle has a velocity of (2.98 i hat - 3.98 j) m/s. Required:
a. Find its x and y components of momentum.
b. Find the magnitude and direction of its momentum.

a) The x and y components of the momentum are and , respectively.

b) The magnitude and direction of its momentum are approximately 14.567 kilogram-meters per second and 306.823º.

Explanation:

a) The vectorial equation of momentum is represented by the following expression:

(1)

Where:

- Vector momentum, measured in kilogram-meters per second.

- Mass of the particle, measured in kilograms.

- Vector velocity, measured in meters per second.

If we know that and , then the momentum is:

The x and y components of the momentum are and , respectively.

b) The magnitude and direction of momentum are represented by the following expressions:

(2)

(3)

Where:

- Magnitude of momentum, measured in kilogram-meters per second.

- Direction of momentum, measured in sexagesimal degrees.

If we know that and , then the magnitude and direction of momentum are, respectively:

The magnitude and direction of its momentum are approximately 14.567 kilogram-meters per second and 306.823º.