You pull horizontally on a 50 kg crate with a force of 400N and the friction force on the crate in 150N. What is the acceleration of the crate?

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Let n be the height of the tree, in inches. then: n/1500=58/6666n=87000n=1318.18 in, or 109.84 ft☺☺☺☺

Average net force: ∑f = fapp + fgrav = 8.20 + (-9.81m/s²)(0.500 kg)           = 3.295 n          = 3.30 nvelocity of object∑f = maa = ∑f / m = 3.295 n / 0.500 kg = 6.59 m/s²v² = v₀² + 2adv = √(v₀² + 2ad)v = √[ 0² + 2(6.59m/s²)(1.50m) ]v = 4.45 m/s