you a viewing a read out on an oscilloscope that shows you when different voltages in a circuit maximize. If the period of the circuit is 0.04 seconds, how much time is there between when the capacitor voltage maximizes and the inductor voltage maximizes ?

there is 0.02 sec between when the capacitor voltage maximizes and the inductor voltage maximizes

Explanation:

Given that time period T = 0.04 sec

Now as the voltage across inductor maximizes, voltage across the capacitor minimizes and vice - versa;

Now, between capacitor maximizing and Inductor maximizing, there is a time of T/2

i.e t = T/2

so from our question; Time period is 0.04sec

now

t = 0.04 / 2

t = 0.02 sec  

Therefore there is 0.02 sec between when the capacitor voltage maximizes and the inductor voltage maximizes

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

i don't understand. explain it clearly