Physics, 23.11.2020 06:50 reyrey216

you a viewing a read out on an oscilloscope that shows you when different voltages in a circuit maximize. If the period of the circuit is 0.04 seconds, how much time is there between when the capacitor voltage maximizes and the inductor voltage maximizes ?

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Answer from: lowemadison047

0.01 s

Explanation:

When the capacitor voltage is maximum, the inductor voltage is at a minimum, and when the capacitor voltage is minimum, the inductor voltage is at a maximum.

The time difference between minimum voltage and maximum voltage for the capacitor or inductor is the same as that for maximum voltage of capacitor to maximum voltage of inductor and this is t = T/4 where T = period.

Since T = 0.04 s, t = T/4

= 0.04 s/4

= 0.01 s

So, the amount of time is there between when the capacitor voltage maximizes and the inductor voltage maximizes is 0.01 s

Answer from: Quest

given data:

determine the horse power (h.p) = ?

force applied to move the box(f) = 10 pounds,

box lifted from a distance (d) = 3 feet

time taken to lift (t) = 10 sec,

the horse power is defined as amount of work required to move a load. the horse power is equal to 550 foot-pound per second

1 h.p = 550 foot-pound/second

it can also be defined as the the load that need to be move a body for certain distance in a certain amount of time.

mathematically,

h.p = (force × distance)/ time

= (10 × 3)/ 10

= 30/10

= 3 foot -pound/sec

hence, the horse power is needed to move the box is 3 foot-pound/second

important note: 1 h.p = 550 foot-pound/second = 746 watts

Answer from: Quest

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

$p(t)=0.3t^2+6t+80$

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

$p(0)=0+0+80=80$

according to question, we have said that if the population has twice its initial population, then it becomes

$p(t)=2\times 80=160$

so, time taken to reach this above mentioned population is given by

$160=0.3t^2+6t+80\\\\160-80=0.3t^2+6t\\\\80=0.3t^2+6t\\\\0.3t^2+6t-80=0\\\\\text{using quadratic formula ,we get }\\\\t_{1,\: 2}=\frac{-60\pm \sqrt{60^2-4\cdot \: 3\cdot \: 800}}{2\cdot \: 3}\\\\t=-29.14\ and\ t=9.149$

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.

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