A spring is 17 cm long when it is lying on a table. One end is then attached to a hook and the other end is pulled by a force that increases to 25 N, causing the spring to stretch to a length of 19.2 cm. How much work was required to stretch the spring? A. 3.13 J
B. 0.552 J
C. 1.67 J
D. 0.276 J

im pretty sure it B but I recommend waiting for another person. I used the workdone formula (Force*Dictance*cos(theta) and got 55 Joules

Explanation:

D. 0.276 J

Explanation:

When I solved this, I got 0.275, so I chose the one closest.

To solve:

convert 17 cm and 19.2 cm to 0.17 m and 0.192 m

W(on spring) = 1/2 (0.192 m - 0.17 m)(25N)

                     = 1/2 (.022 m)(25 N)

                     = 0.275

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards