. You are standing at the top of a high cliff. You drop a rock and it hits the ground 4 seconds later. How fast was it going when it hits the ground?

V = -39.2m/s

Explanation:

Given the following data

Time, t = 4secs

Since the rock is falling, we know that the initial velocity = 0

Acceleration due to gravity = 9.8m/s²

To find the final velocity, we would use the first equation of motion

V = U + at

Substituting into the equation, we have

V = 0 + (-9.8*4)

V = -39.2m/s

b) returns freshwater to the earth.

c) returns freshwater to the earth.c) occurs after condensation.

d) returns freshwater to the earth.c) occurs after condensation.d) roughly equal to the amount of evaporation.

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