D) A tank with dimensions: 3m x 2m x 2m contains water upto its half pertion. What is the pressure at the base of the tank? (density of water
= 1000 kg/m3, g= 9.8 m/s2)
(Ans: 9800 Pa)

P = 9800 [Pa]

Explanation:

In order to calculate the pressure at the bottom, we must use the following formula.

P = Ro*g*h

where:

P = pressure [Pa] (units of pascals)

Ro = density of the water = 1000 [kg/m³]

g = gravity acceleration = 9.8 [m/s²]

h = height = 1 [m] (because its half of the portion, the full height is 2 m)

P = 1000*9.8*1

P = 9800 [Pa]

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