A 0.25 Kg object is projected vertically into the air with a velocity of 45 m/s. How high above the ground is the object after 4.3 seconds? A) 103 m
B) 0 m
C) 87 m
D) 121 m

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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your answer is, orbit around the nucleus

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2

god i hope this !