if 1.5kg block is pulled across a horizontal surface that has a coefficient of kintic friction of 0.60. if a block is pulled by a 12n force, what is the net force acting on the block

3.2N

Explanation:

Given parameters:

Mass of block  = 1.5kg

Coefficient of kinetic friction  = 0.6

Force of pull on block  = 12N

Unknown:

Net force on the block  = ?

Solution:

Frictional force is a force that opposes motion:

  Net force  = Force of pull  - Frictional force

 Frictional force  = umg

   u is coefficient of kinetic friction

   m is the mass

    g is the acceleration due to gravity

 Frictional force  = 0.6 x 1.5 x 9.8  = 8.8N

 Net force  = 12N  - 8.8N  = 3.2N

i think the answer is a, hope this : )