A car moving with a velocity of 15 m/s accelerates to a velocity of 37 m/s in 3.2 seconds. what's the car's rate of acceleration? given:
find:
formulas:
manipulate:
substitute:

a = 6.87 [m/s²]

Explanation:

To solve this problem we must use the following equation of kinematics.

where:

Vf = final velocity = 37 [m/s]

Vo = initial velocity = 15 [m/s]

a = acceleration [m/s²]

t = time = 3.2 [s]

Note: The positive sign in the above equation means that the velocity is increasing, due to the acceleration.

37 = 15 + a*3.2

3.2*a = 37 - 15

a = 6.87 [m/s²]

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