A 7.5 Kg cannon ball leaves a canon with a speed of 185 meters per second. Find the average net force applied to the ball is the canon muzzle is 3.6 meters long

F = 35651 [N]

Explanation:

To solve this problem we must use the following equation of kinematics

where:

Vf = final velocity = 185 [m/s]

Vo = initial velocity = 0 (starts from the rest)

a = acceleration [m/s²]

x = distance = 3.6 [m]

Now we can find the acceleration.

185² = 0 + 2*a*3.6

34225 = 7.2*a

a = 4753.47 [m/s²]

Now we must use Newton's second law which tells us that the total force on a body is equal to the product of mass by acceleration.

F = m*a

where:

m = mass = 7.5 [kg]

F = force [N] (units of Newtons)

F = 7.5*4753.47

F = 35651 [N]

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be

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