A student performs an activity using a sheet of paper, a magnet, and a steel ball. The image shows the setup. The student observes that the steel ball sticks to the magnet even though, the paper is between them. Which factor leads to the attraction of the ball to the magnet. A. The magnet exerts a force on the ball.
B. The magnet attracts paper, which pulls the ball. C. The paper exerts a force on the ball, Which pulls the ball towards the magnet.
D. The size of the ball attracts to the ball towards the magnet.

Simple harmonic motion wind energy circulation best answer from the choices

One splits the atoms and molecules  the other combines them

Answer: a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same sign as the  -4.0  µc charge.======electricstatic force between two point charges  is given by    where k is coulomb's constant,  8.99×10⁹  n·m²/c², q₁ and q₂ are the point charges, and r is the distance between the two point charges.assign positive to q₁let q₁ =  6.0 µc, q₂ = -4.0  µc, q₀ represent the charge at the origin, and q₃ represent this new charge to place.the charge at the origin q₀ would experience the following force f₀₁ from q₁, with r = 6.0 m (note that 1  µc = 10⁻⁶ c)    the force from q₂    the force from q₃    the net force on the origin charge, q₀, has to be zero for no electrostatic forcehaving an equation where k and q₀ can be divided out of the equation will allow us to solve for q₃    isolating:     a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same as the  -4.0  µc charge