Calculate the height from which a body is released rest if its velocity just before hitting the ground is 30ms-1

45.9m

Explanation:

Given parameters:

Final velocity  = 30m/s

Initial velocity  = 0m/s

Unknown:

Height of fall  = ?

Solution:

  The motion equation to solve this problem is given below;

            V² = U² + 2gH

            V²  = 0 + (2 x 9.8 x H)

           30²  = 19.6H

              H =   = 45.9m

search it up!

explanation:

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle