A barrel of oil contains roughly 6.1×109 J. How many kW-hr is this? Answer in units of kW-hr

Energy is the ability to do work. There are a few types of energy, these types are as follows:-

The barrel of oil contains around 6.1*10^9 J of energy.  We want this energy expressed in kW-hr.

One joule of energy has   1J = 2.78*10^(-7) kW-hr .

Therefore, the J will be equal to times the above amount.

Hence, the energy will be

E =    

 =

=  

Hence, the correct option is    

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1.6958*10^3 kW-hr

Explanation:

The barrel of oil contains around 6.1*10^9 J of energy.

We want this energy expressed in kW-hr.

We know that:

1J = 2.78*10^(-7) kW-hr

Then  6.1*10^9 J will be equal to 6.1*10^9  times the above amount.

This is:

E =  (6.1*10^9)*(2.78*10^(-7) kW-hr) = (6.1*2.78)*(10^9*10^(-7)) kW-hr

  = 16.958*10^(9 - 7) kW-hr

  =  16.958*10^2 kW-hr

  = 1.6958*10^3 kW-hr