1000 kg car takes travels on a circular track having radius 100 m with speed 10 m/s. What is the minimum coefficient of static friction between tires and track needed to keep the car on circular path.

μ = 0.1

Explanation:

In order to keep the car on circular track, the centripetal force must be equal to the frictional force between tires and track:

Frictional Force = Centripetal Force

μmg = mv²/r

μ = v²/gr

where,

μ = coefficient of friction = ?

v = speed of car = 10 m/s

g = 9.8 m/s²

r = radius of track = 100 m

Therefore,

μ = (10 m/s)²/(9.8 m/s²)(100 m)

μ = 0.1

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