جسم كتلته (m=0.9 kg)  معلق بخيط مهمل الكتله طوله (L=3m) ويتحرك في دائرة افقية بسرعة مناسبة مقدارها (v=3m/s). ما مقدار القوة التي يؤثر بها الخيط في الجسم ؟

9 N

Explanation:

The centripetal force F is F = mrω^2 = (mv^2)/r where m is mass, r is radius of the curve, ω is angular velocity and v is tangential velocity.

In this case, m = 0.5kg, r = 0.5m, v = 3m/s

So F = [0.5kg(3m/s)^2]/0.5m = 9kg-m/s^2 which is 9N

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