a ball is rolling ar 4.80m/s over level ground when it encounters a ramp which gives it an acceleration of -0.875m/s^{2. if the ramp is 0.750m long, what is the final velocity of the ball when it reaches the top of the ramp?

4.66m/s

Explanation:

Given parameters:

Initial velocity  = 4.8m/s

Acceleration = -0875m/s²

Length of the ramp  = 0.75m

Unknown:

Final velocity  = ?

Solution:

To solve this problem, we apply the right motion equation;

     V² = U²  +  2aS

V is the final velocity

U is the initial velocity

a is the acceleration

S is the distance  = length of ramp

   Insert the parameters;

      V²   = 4.8²  + 2(-0.875)0.75

      V²   = 23.04 - 1.31

      V²  = 21.73

      V = √21.73  = 4.66m/s

you have to draw the persons position over there

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation: