A cannon sitting on the edge of a cliff 500 meters above the ground shoots a cannon ball with a horizontal velocity of 100m/s. At some point the cannon hits the ground. How far away from the point it was launched will the cannon ball land?

1010 m

Explanation:

The following data were obtained from the question:

Height (h) of cliff = 500 m

Horizontal velocity (u) = 100 m/s

Horizontal distance (s) =?

Next we shall determine the time taken for the cannon ball to hit the ground. This can be obtained as follow:

Height (h) of cliff = 500 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

500 = ½ × 9.8 × t²

500 = 4.9 × t²

Divide both side by 4.9

t² = 500/4.9

Take the square root of both side

t = √(500/4.9)

t = 10.1 s

Finally, we shall determine the horizontal distance travelled by the cannon ball.

This can be obtained by using the following formula (s = ut) as illustrated below:

Horizontal velocity (u) = 100 m/s

Time (t) = 10.1 s

Horizontal distance (s) =?

s = ut

s = 100 × 10.1

s = 1010 m

Thus, the cannon ball was launched 1010 m away from the cliff.

are their multiple choices ?

explanation:

graph slopes whilst gas cools, then it is flat whilst conensation to liquid happens, the coolong liquid then graphs as a slope when it solidifies graph is flat

latent heat